The total heat in BTU's required to convert 10lbs of ice at 32 degrees Fahrenheit to water at 82 degrees Fahrenheit is?

To determine the total heat required to convert 10 lbs of ice at 32 degrees Fahrenheit to water at 82 degrees Fahrenheit, we need to consider two key processes: melting the ice and then heating the resulting water.

First, when ice at 32°F melts to water, it requires a specific amount of heat known as the heat of fusion. For water, the heat of fusion is approximately 144 BTUs per pound. Therefore, to melt 10 lbs of ice, the calculation would be:

10 lbs x 144 BTU/lb = 1440 BTUs.

Next, after the ice has completely turned into water, the water must be heated from 32°F to 82°F. The specific heat of water is about 1 BTU per pound per degree Fahrenheit. To calculate the heat required to raise the temperature of 10 lbs of water from 32°F to 82°F, you first find the temperature change:

82°F - 32°F = 50°F.

Then, the calculation for heating the water would be:

10 lbs x 50°F x 1 BTU/lb°F = 500 BTUs.

Adding the heat required for both processes gives the total heat requirement:

1440 BTUs (